
PRACTICE EXERCISES ON RADIOMETRIC
DATING
Geosciences
II Fall 2009
NAME ______KEY_______________________
(Please note that P
indicates parent material and D indicates daughter material.)
1) On the chart provided below, fill in the abundances of the parent and daughter material at the various half-lives labeled at the top of the chart.
|
Number of half-lives |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
|
% Parent
Material |
100 |
50 |
25 |
12.5 |
6.25 |
3.125 |
1.5625 |
.78125 |
|
% Daughter Material |
0 |
50 |
75 |
87.5 |
93.75 |
96.875 |
98.4375 |
99.21875 |
2) Using the above chart, estimate the
percentage of parent and daughter material that should be present if 5
half-lives have passed. If the length
of a half-life is 4 million years, how old is the rock?
3.125% Parent and 96.875% Daughter
Age = 5 half lives x 4MY/half life = 20 Million Years
3) What is the
age of a basaltic lava flow which has isotopic abundances of D=87.5%
and P=12.5% and an isotopic half-life of 8
million years?
If D=87.5% and P=12.5%, then 3 half lives have passed.
Age = 3 half lives x 8MY/half life =
24Million Years
4) What is the age of a volcanic ash
layer that contains an isotope with an abundance of D=98.4375% and a half-life
of 2.5 million years? What percentage
of the isotope would remain as parent material?
If D=98.4375%, then 6 half lives have
passed.
Age = 6 half lives x 2.5MY/half life =
15 Million Years
P=1.5625%
5) What is the age a granite intrusion
which has an isotopic abundance of P=3.125% and a half-life of 18 million
years? What percentage of this isotope
should be found as daughter material in this rock?
If P=3.125%, then 5 half lives have passed.
Age = 5 half lives x 18MY/half life = 90 Million Years
D=96.875%
6) Two separate isotopes were measured
in a rock to determine its age. Isotope
A has a half-life of 6.1 million years and 6.25% of the isotope is found as
parent material (P=6.25%). Isotope B
has a half-life of 2.8 million years and 1.5625% of isotope B is found as
parent material. Determine the age
based on each isotope. Do these ages
agree? Explain.
Isotope A : P=6.25% so 4 half lives have passed.
Age
= 4 half lives x 6.1MY/half life = 24.4 Million Years
Isotope B : P=1.5625% so 6 half lives have passed.
Age
= 6 half lives x 2.8MY/half life = 16.8 Million Years
The ages do not agree, so one or both must be wrong.
7) A moon-rock sample was dated with 2
separate isotopes, yielding the following results: Isotope A has a half-life of
1.5 billion years and 12.5% of the
isotope is found as parent material (P=12.5%).
Isotope B has a half-life of 750 million years and 1.5625% of isotope B
is found as parent material. Determine
the age based on each isotope. Do these
ages agree? Explain.
Isotope A : P=12.5% so
3 half lives have passed.
Age
= 3 half lives x 1.5BY/half life = 4.5 Billion Years
Isotope B : P=1.5625% so 6 half lives have passed.
Age
= 6 half lives x 750MY/half life = 4,500 Million Years = 4.5 Billion Years
The ages do agree and support one another.
8) Why can't accurate age
determinations be obtained from clastic (detrital) sedimentary rocks (like
conglomerates)? Explain.
Because the radiometric isotopes are reset when the clastic sedimentary rocks are formed. They form at too low of temperatures and pressures. The age of a clastic rock would consist of a composite or average age of the igneous and metamorphic rock fragments that make up the rock.